Let p, q ∈ R and (1-√ 3 i)^200=2^199(p+i q), i=√ -1 Then p + q + q^2 and p - q + q^2 are roots of the equation.

Let $\displaystyle \mathrm{p}, \mathrm{q} \in \mathbb{R}$ and $\displaystyle (1-\sqrt{3} i)^{200}=2^{199}(p+i q), i=\sqrt{-1}$ Then $\displaystyle \mathrm{p}+\mathrm{q}+\mathrm{q}^2$ and $\displaystyle \mathrm{p}-\mathrm{q}+\mathrm{q}^2$ are roots of the equation.