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Mathematics · 2024

JEE Main · 1 February 2024, Shift 2 · Q4

Let α and β be the roots of the equation p x^2+q x-r=0, where p ≠ 0. If p, q and r be the consecutive terms of a non constant G.P. and…

Let $\displaystyle \alpha$ and $\displaystyle \beta$ be the roots of the equation $\displaystyle p x^2+q x-r=0$, where $\displaystyle p \neq 0$. If $\displaystyle p$, $\displaystyle q$ and $\displaystyle r$ be the consecutive terms of a non constant G.P. and $\displaystyle \frac{1}{\alpha}+\frac{1}{\beta}=\frac{3}{4}$, then the value of $\displaystyle (\alpha-\beta)^2$ is :
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.