Mathematics · 2024
JEE Main · 1 February 2024, Shift 1 · Q2
Let S={x ∈ R:(√ 3 +√ 2 )^x+(√ 3 -√ 2 )^x=10}. Then the number of elements in S is:
Let $\displaystyle S=\left\{x \in \mathbf{R}:(\sqrt{3}+\sqrt{2})^x+(\sqrt{3}-\sqrt{2})^x=10\right\}$. Then the number of elements in $\displaystyle S$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 2$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.