Mathematics · 2024
JEE Main · 4 April 2024, Shift 1 · Q3
If 2 and 6 are the roots of the equation a x^2+b x+1=0, then the quadratic equation, whose roots are 1/(2 a+b) and 1/(6 a+b), is:
If $\displaystyle 2$ and $\displaystyle 6$ are the roots of the equation $\displaystyle a x^2+b x+1=0$, then the quadratic equation, whose roots are $\displaystyle \frac{1}{2 a+b}$ and $\displaystyle \frac{1}{6 a+b}$, is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle x^2+8 x+12=0$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.