Let a straight line L pass through the point P (2,-1,3) and be perpendicular to the lines (x-1)/2=(y+1)/1=(z-3)/-2 and (x-3)/1=(y-2)/3=(z+2)/4. If…

Let a straight line L pass through the point $\displaystyle \mathrm{P}(2,-1,3)$ and be perpendicular to the lines $\displaystyle \frac{x-1}{2}=\frac{y+1}{1}=\frac{z-3}{-2}$ and $\displaystyle \frac{x-3}{1}=\frac{y-2}{3}=\frac{z+2}{4}$. If the line L intersects the $\displaystyle y z$-plane at the point Q , then the distance between the points P and Q is :