Let a complex number be w =1-√ 3 i. Let another complex number z be such that |z w|=1 and (z)- (w)=(π)/2. Then the area of the triangle with vertices…

Let a complex number be $\displaystyle \mathrm{w}=1-\sqrt{3} i$. Let another complex number $\displaystyle z$ be such that $\displaystyle |z w|=1$ and $\displaystyle \arg (z)-\arg (w)=\frac{\pi}{2}$. Then the area of the triangle with vertices origin, $\displaystyle z$ and $\displaystyle w$ is equal to :