Mathematics · 2019
JEE Main · 12 April 2019, Shift 2 · Q70
lim_x → 0 (x+2 sin x)/(√(x^2+2 sin x+1)-√(sin^2 x-x+1)) is:
$$\lim _{x \rightarrow 0} \frac{x+2 \sin x}{\sqrt{x^2+2 \sin x+1}-\sqrt{\sin ^2 x-x+1}}
$$
is :
Official answer
(2)
$\displaystyle 2$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.