Mathematics · 2019
JEE Main · 12 January 2019, Shift 1 · Q70
lim_x → π / 4 (cot^3 x- tan x)/(cos (x+π / 4)) is:
$\displaystyle \lim _{x \rightarrow \pi / 4} \frac{\cot ^3 x-\tan x}{\cos (x+\pi / 4)}$ is :
Official answer
(4)
$\displaystyle 8$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.