Mathematics · 2016
JEE Main · 10 April 2016, Shift 1 · Q70
lim_x → 0 ((1- cos 2 x)^2)/(2 x tan x-x tan 2 x) is:
$\displaystyle \lim _{x \rightarrow 0} \frac{(1-\cos 2 x)^2}{2 x \tan x-x \tan 2 x}$ is :
Official answer
(1)
$\displaystyle -2$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.