Mathematics · 2022
JEE Main · 27 June 2022, Shift 1 · Q19
sin^-1( sin (2 π)/3)+ cos^-1( cos (7 π)/6)+ tan^-1( tan (3 π)/4) is equal to:
$\displaystyle \sin ^{-1}\left(\sin \frac{2 \pi}{3}\right)+\cos ^{-1}\left(\cos \frac{7 \pi}{6}\right)+\tan ^{-1}\left(\tan \frac{3 \pi}{4}\right)$ is equal to :
Official answer
(1)
$\displaystyle \frac{11 \pi}{12}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.