Mathematics · 2022
JEE Main · 25 July 2022, Shift 2 · Q6
lim_x → (π)/4 (8 √ 2 -( cos x+ sin x)^7)/(√ 2 -√ 2 sin 2 x) is equal to
$\displaystyle \lim _{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^7}{\sqrt{2}-\sqrt{2} \sin 2 x}$ is equal to
Official answer
(1)
$\displaystyle 14$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.