Mathematics · 2020
JEE Main · 3 September 2020, Shift 2 · Q57
lim_x → a ((a+2 x)^(1/3)-(3 x)^(1/3))/((3 a+x)^(1/3)-(4 x)^(1/3))(a ≠ 0) is equal to:
$\displaystyle \lim _{x \rightarrow a} \frac{(a+2 x)^{\frac{1}{3}}-(3 x)^{\frac{1}{3}}}{(3 a+x)^{\frac{1}{3}}-(4 x)^{\frac{1}{3}}}(a \neq 0)$ is equal to :
Official answer
(4)
$\displaystyle \left(\frac{2}{3}\right)\left(\frac{2}{9}\right)^{\frac{1}{3}}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.