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Mathematics · 2020
JEE Main · 7 January 2020, Shift 1 · Q73
lim_x → 2 (3^x+3^3-x-12)/(3^-x / 2-3^1-x) is equal to \ \ \ \
$\displaystyle \lim _{x \rightarrow 2} \frac{3^x+3^{3-x}-12}{3^{-x / 2}-3^{1-x}}$ is equal to
\_\_\_\_
Official answer
36
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.