Mathematics · 2022
JEE Main · 25 July 2022, Shift 2 · Q7
lim_n → ∞ 1/2^n(1/(√(1-1/2^n))+1/(√(1-2/2^n))+1/(√(1-3/2^n))+….+1/(√(1-(2^n-1)/2^n))) is equal to
$\displaystyle \lim _{n \rightarrow \infty} \frac{1}{2^n}\left(\frac{1}{\sqrt{1-\dfrac{1}{2^n}}}+\frac{1}{\sqrt{1-\dfrac{2}{2^n}}}+\frac{1}{\sqrt{1-\dfrac{3}{2^n}}}+\ldots .+\frac{1}{\sqrt{1-\dfrac{2^n-1}{2^n}}}\right)$ is equal to
Official answer
(3)
$\displaystyle 2$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.