Mathematics · 2022
JEE Main · 26 July 2022, Shift 1 · Q26
If n (2 n +1) ∫_0^1(1-x^n )^2 n d x=1177 ∫_0^1(1-x^n )^2 n +1 d x, then n ∈ N is equal to \ \ \ \.
If $\displaystyle \mathrm{n}(2 \mathrm{n}+1) \int_0^1\left(1-x^{\mathrm{n}}\right)^{2 \mathrm{n}} \mathrm{d} x=1177 \int_0^1\left(1-x^{\mathrm{n}}\right)^{2 \mathrm{n}+1} \mathrm{~d} x$, then $\displaystyle \mathrm{n} \in \mathbf{N}$ is equal to \_\_\_\_.
Official answer
24
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.