Mathematics · 2023
JEE Main · 24 January 2023, Shift 1 · Q67
tan^-1((1+√ 3)/(3+√ 3))+ sec^-1(√((8+4 √ 3)/(6+3 √ 3))) is equal to:
$\displaystyle \tan ^{-1}\left(\frac{1+\sqrt{3}}{3+\sqrt{3}}\right)+\sec ^{-1}\left(\sqrt{\frac{8+4 \sqrt{3}}{6+3 \sqrt{3}}}\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{\pi}{3}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.