Mathematics · 2020
JEE Main · 2 September 2020, Shift 2 · Q59
lim_x → 0( tan ((π)/4+x))^1 / x is equal to:
$\displaystyle \lim _{x \rightarrow 0}\left(\tan \left(\frac{\pi}{4}+x\right)\right)^{1 / x}$ is equal to :
Official answer
(4)
$\displaystyle e^2$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.