Mathematics · 2019
JEE Main · 10 April 2019, Shift 2 · Q88
If cos^-1 x- cos^-1 y/2=α, where -1 ≤ x ≤ 1, -2 ≤ y ≤ 2, x ≤ y/2, then for all x, y, 4 x^2-4 x y cos α+y^2 is equal to:
If $\displaystyle \cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\alpha$, where $\displaystyle -1 \leq x \leq 1$,
$\displaystyle -2 \leq y \leq 2, x \leq \frac{y}{2}$, then for all $\displaystyle x, y$,
$\displaystyle 4 x^2-4 x y \cos \alpha+y^2$ is equal to :
Official answer
(3)
$\displaystyle 4 \sin ^2 \alpha$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.