Mathematics · 2021
JEE Main · 26 February 2021, Shift 1 · Q76
If (sin^-1 x)/a=(cos^-1 x)/b=(tan^-1 y)/c; 0<x<1, then the value of cos ((π c)/(a + b)) is:
If $\displaystyle \frac{\sin ^{-1} x}{\mathrm{a}}=\frac{\cos ^{-1} x}{\mathrm{~b}}=\frac{\tan ^{-1} y}{\mathrm{c}} ; 0<x<1$, then the value of $\displaystyle \cos \left(\frac{\pi \mathrm{c}}{\mathrm{a}+\mathrm{b}}\right)$ is :
Official answer
(3)
$\displaystyle \frac{1-y^2}{1+y^2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.