Mathematics · 2020
JEE Main · 3 September 2020, Shift 1 · Q71
If ((1+i)/(1-i))^m / 2 =((1+i)/(i-1))^n / 3 =1, ( m, n ∈ N ) then the greatest common divisor of the least values of m and n is \ \ \ \.
If $\displaystyle \left(\frac{1+i}{1-i}\right)^{\mathrm{m} / 2}=\left(\frac{1+i}{i-1}\right)^{\mathrm{n} / 3}=1, \quad(\mathrm{~m}, \quad \mathrm{n} \in \mathbf{N})$ then the greatest common divisor of the least values of m and n is \_\_\_\_.
Official answer
4
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.