Mathematics · 2024
JEE Main · 29 January 2024, Shift 1 · Q1
If f(x)={ 2+2 x, -1 ≤ x<0; 1-x/3, 0 ≤ x ≤ 3; g(x)= {-x, -3 ≤ x ≤ 0; x, 0<x ≤ 1}., then range of (f ° g)(x) is
If $\displaystyle f(x)=\left\{\begin{array}{cc}2+2 x, & -1 \leq x<0 \\ 1-\frac{x}{3}, & 0 \leq x \leq 3\end{array} ; g(x)=\left\{\begin{array}{cc}-x, & -3 \leq x \leq 0 \\ x, & 0<x \leq 1\end{array}\right.\right.$, then range of $\displaystyle (f \circ g)(x)$ is
Official answer
From NTA’s final answer key for this paper.
(2)
[$\displaystyle 0,1$]
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.