Mathematics · 2020
JEE Main · 3 September 2020, Shift 1 · Q57
If y^2+ log_e ( cos^2 x)=y, x ∈(-(π)/2, (π)/2), then:
If $\displaystyle y^2+\log _{\mathrm{e}}\left(\cos ^2 x\right)=y, \quad x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$,
then :
Official answer
(4)
$\displaystyle \left|y^{\prime \prime}(0)\right|=2$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.