Mathematics · 2022
JEE Main · 27 June 2022, Shift 1 · Q11
If (d y)/(d x)+(2^x-y(2^y-1))/(2^x-1)=0, x, y>0, y(1)=1, then y(2) is equal to:
If $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}+\frac{2^{x-y}\left(2^y-1\right)}{2^x-1}=0, x, y>0, y(1)=1$, then $\displaystyle y(2)$ is equal to :
Official answer
(4)
$\displaystyle 2-\log _2 3$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.