Mathematics · 2024
JEE Main · 1 February 2024, Shift 2 · Q25
If y=((√ x +1)(x^2-√ x ))/(x √ x +x+√ x)+1/15(3 cos^2 x-5) cos^3 x, then 96 y^′((π)/6) is equal to ____.
If $\displaystyle y=\frac{(\sqrt{x}+1)\left(x^2-\sqrt{x}\right)}{x \sqrt{x}+x+\sqrt{x}}+\frac{1}{15}\left(3 \cos ^2 x-5\right) \cos ^3 x$, then $\displaystyle 96 y^{\prime}\left(\frac{\pi}{6}\right)$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
105
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.