Mathematics · 2024
JEE Main · 5 April 2024, Shift 2 · Q20
If y(θ)=(2 cos θ+ cos 2 θ)/(cos 3 θ+4 cos 2 θ+5 cos θ+2), then at θ=(π)/2, y^′ ′+y^′+y is equal to:
If $\displaystyle y(\theta)=\frac{2 \cos \theta+\cos 2 \theta}{\cos 3 \theta+4 \cos 2 \theta+5 \cos \theta+2}$, then at $\displaystyle \theta=\frac{\pi}{2}, y^{\prime \prime}+y^{\prime}+y$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 2$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.