Mathematics · 2021
JEE Main · 16 March 2021, Shift 1 · Q84
If lim_x → 0 (ae^x- b cos x+ ce^-x)/(x sin x)=2, then a + b + c is equal to \ \ \ \.
If $\displaystyle \lim _{x \rightarrow 0} \frac{\mathrm{ae}^x-\mathrm{b} \cos x+\mathrm{ce}^{-x}}{x \sin x}=2$, then $\displaystyle \mathrm{a}+\mathrm{b}+\mathrm{c}$ is equal to \_\_\_\_.
Official answer
4
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.