Mathematics · 2023
JEE Main · 12 April 2023, Shift 1 · Q6
If 1/(n+1)^n C_n+1/n^n C_n-1+…+1/2^n C_1+^n C_0=1023/10 then n is equal to
If $\displaystyle \frac{1}{n+1}{ }^n \mathrm{C}_n+\frac{1}{n}{ }^n \mathrm{C}_{n-1}+\ldots+\frac{1}{2}{ }^n \mathrm{C}_1+{ }^n \mathrm{C}_0=\frac{1023}{10}$ then $\displaystyle n$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 9$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.