Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q71
If (d y)/(d x)=(2^x+y-2^x)/2^y, y(0)=1, then y(1) is equal to:
If $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{2^{x+y}-2^x}{2^y}, y(0)=1$, then $\displaystyle y(1)$ is equal to :
Official answer
(4)
$\displaystyle \log _2(1+\mathrm{e})$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.