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Mathematics · 2021

JEE Main · 3 August 2021, Shift 2 · Q87

If the solution y=y(x) of the differential equation (y+3 x^4) (d x)/(d y)=x, x>0, satisfieds y(1)=-1, then the value of (d^2 y)/(d x^2)-(d y)/(d x)+y…

If the solution $\displaystyle y=y(x)$ of the differential equation $\displaystyle \left(y+3 x^4\right) \frac{d x}{d y}=x, x>0$, satisfieds $\displaystyle y(1)=-1$, then the value of $\displaystyle \frac{d^2 y}{d x^2}-\frac{d y}{d x}+y$ at $\displaystyle x=2$ is \_\_\_\_.
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