Mathematics · 2021
JEE Main · 22 July 2021, Shift 2 · Q63
If the shortest distance between the straight lines 3(x-1)=6(y-2)=2(z-1) and 4(x-2)=2(y-λ)=(z-3), λ ∈ R is 1/(√ 38), then the integral value of λ is…
If the shortest distance between the straight lines $\displaystyle 3(x-1)=6(y-2)=2(z-1)$ and $\displaystyle 4(x-2)=2(y-\lambda)=(z-3), \lambda \in \mathbf{R}$ is $\displaystyle \frac{1}{\sqrt{38}}$, then the integral value of $\displaystyle \lambda$ is equal to:
Official answer
(3)
$\displaystyle 3$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.