Mathematics · 2025
JEE Main · 7 April 2025, Shift 2 · Q2
If the range of the function f(x)=(5-x)/(x^2-3 x+2), x ≠ 1,2, is (-∞, α] ∪[β, ∞), then α^2+β^2 is equal to:
If the range of the function $\displaystyle f(x)=\frac{5-x}{x^2-3 x+2}, x \neq 1,2$, is $\displaystyle (-\infty, \alpha] \cup[\beta, \infty)$, then $\displaystyle \alpha^2+\beta^2$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 194$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.