Mathematics · 2019
JEE Main · 9 January 2019, Shift 2 · Q83
If the lines x= a y+ b, z= c y+ d and x= a^′ z+ b^′, y= c^′ z+ d^′ are perpendicular, then:
If the lines $\displaystyle x=\mathrm{a} y+\mathrm{b}, z=\mathrm{c} y+\mathrm{d}$ and $\displaystyle x=\mathrm{a}^{\prime} z+\mathrm{b}^{\prime}, y=\mathrm{c}^{\prime} z+\mathrm{d}^{\prime}$ are perpendicular, then :
Official answer
(3)
$\displaystyle a a^{\prime}+c+c^{\prime}=0$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.