Mathematics · 2021
JEE Main · 25 July 2021, Shift 2 · Q82
If the lines (x-k)/1=(y-2)/2=(z-3)/3 and (x+1)/3=(y+2)/2=(z+3)/1 are co-planar, then the value of k is \ \ \ \.
If the lines $\displaystyle \frac{x-k}{1}=\frac{y-2}{2}=\frac{z-3}{3}$ and $\displaystyle \frac{x+1}{3}=\frac{y+2}{2}=\frac{z+3}{1}$ are co-planar, then the value of k is \_\_\_\_.
Official answer
1
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.