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Mathematics · 2026

JEE Main · 23 January 2026, Shift 2 · Q23

If the image of the point P (a, 2, a) in the line x/2=(y+a)/1=z/1 is Q and the image of Q in the line (x-2 b)/2=(y-a)/1=(z+2 b)/-5 is P, then a+b is…

If the image of the point $\displaystyle \mathrm{P}(a, 2, a)$ in the line $\displaystyle \frac{x}{2}=\frac{y+a}{1}=\frac{z}{1}$ is Q and the image of Q in the line $\displaystyle \frac{x-2 b}{2}=\frac{y-a}{1}=\frac{z+2 b}{-5}$ is P , then $\displaystyle a+b$ is equal to $\displaystyle \_\_\_\_$.
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.