Mathematics · 2021
JEE Main · 16 March 2021, Shift 2 · Q61
If the foot of the perpendicular from point (4,3,8) on the line L_1: (x- a)/l=(y-2)/3=(z- b)/4, l ≠ 0 is (3,5,7), then the shortest distance between…
If the foot of the perpendicular from point $\displaystyle (4,3,8)$ on the line $\displaystyle \mathrm{L}_1: \frac{x-\mathrm{a}}{l}=\frac{y-2}{3}=\frac{z-\mathrm{b}}{4}$, $\displaystyle l \neq 0$ is $\displaystyle (3,5,7)$, then the shortest distance between the line $\displaystyle \mathrm{L}_1$ and line $\displaystyle \mathrm{L}_2: \frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5}$ is equal to :
Official answer
(1)
$\displaystyle \frac{1}{\sqrt{6}}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.