Mathematics · 2024
JEE Main · 1 February 2024, Shift 2 · Q1
If the domain of the function f(x)=(√(x^2-25))/((4-x^2))+ log_10(x^2+2 x-15) is (-∞, α) ∪[β, ∞), then α^2+β^3 is equal to:
If the domain of the function $\displaystyle f(x)=\frac{\sqrt{x^2-25}}{\left(4-x^2\right)}+\log _{10}\left(x^2+2 x-15\right)$ is $\displaystyle (-\infty, \alpha) \cup[\beta, \infty)$, then $\displaystyle \alpha^2+\beta^3$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 150$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.