Mathematics · 2025
JEE Main · 2 April 2025, Shift 2 · Q1
If the domain of the function f(x)=1/(√(10+3 x-x^2))+1/(√(x+|x|)) is ( a, b ), then (1+ a )^2+ b^2 is equal to:
If the domain of the function $\displaystyle f(x)=\frac{1}{\sqrt{10+3 x-x^2}}+\frac{1}{\sqrt{x+|x|}}$ is $\displaystyle (\mathrm{a}, \mathrm{b})$, then $\displaystyle (1+\mathrm{a})^2+\mathrm{b}^2$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 26$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.