Mathematics · 2021
JEE Main · 16 March 2021, Shift 2 · Q83
If the distance of the point (1,-2,3) from the plane x+2 y-3 z+10=0 measured parallel to the line, (x-1)/3=(2-y)/m=(z+3)/1 is √(7/2), then the value…
If the distance of the point $\displaystyle (1,-2,3)$ from the plane $\displaystyle x+2 y-3 z+10=0$ measured parallel to the line, $\displaystyle \frac{x-1}{3}=\frac{2-y}{\mathrm{~m}}=\frac{z+3}{1}$ is $\displaystyle \sqrt{\frac{7}{2}}$, then the value of $\displaystyle |\mathrm{m}|$ is equal to \_\_\_\_.
Official answer
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.