If the distance between the plane, 23 x-10 y-2 z+48=0 and the plane containing the lines (x+1)/2=(y-3)/4=(z+1)/3 and (x+3)/2=(y+2)/6=(z-1)/(λ)(λ ∈ R…

If the distance between the plane, $\displaystyle 23 x-10 y-2 z+48=0$ and the plane containing the lines $$\frac{x+1}{2}=\frac{y-3}{4}=\frac{z+1}{3} $$ and $\displaystyle \frac{x+3}{2}=\frac{y+2}{6}=\frac{z-1}{\lambda}(\lambda \in \mathbf{R})$ is equal to $\displaystyle \frac{k}{\sqrt{633}}$, then $\displaystyle k$ is equal to \_\_\_\_.