Mathematics · 2014
JEE Main · 12 April 2014, Shift 1 · Q84
If the distance between planes, 4 x-2 y-4 z+1=0 and 4 x-2 y-4 z+ d =0 is 7, then d is:
If the distance between planes,
$$\begin{aligned}
& 4 x-2 y-4 z+1=0 \text { and } \\
& 4 x-2 y-4 z+\mathrm{d}=0 \text { is } 7, \text { then } \mathrm{d} \text { is : }
\end{aligned}
$$
Official answer
(3)
-$\displaystyle 41$ or $\displaystyle 43$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.