Mathematics · 2024
JEE Main · 5 April 2024, Shift 1 · Q24
If the constant term in the expansion of (1+2 x-3 x^3)(3/2 x^2-1/(3 x))^9 is p, then 108p is equal to ____.
If the constant term in the expansion of $\displaystyle \left(1+2 x-3 x^3\right)\left(\frac{3}{2} x^2-\frac{1}{3 x}\right)^9$ is p, then 108p is equal to
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
54
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.