Mathematics · 2014
JEE Main · 19 April 2014, Shift 1 · Q84
If the angle between the line 2(x+1)=y=z+4 and the plane 2 x-y+√ λ z+4=0 is (π)/6, then the value of λ is:
If the angle between the line $\displaystyle 2(x+1)=y=z+4$ and the plane $\displaystyle 2 x-y+\sqrt{\lambda} z+4=0$ is $\displaystyle \frac{\pi}{6}$, then the value of $\displaystyle \lambda$ is :
Official answer
(3)
$\displaystyle \frac{45}{7}$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.