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Mathematics · 2013

JEE Main · 22 April 2013, Shift 1 · Q72

If the 7th term in the binomial expansion of (3/(√[3] 84)+√ 3 ln x)^9, x>0, is equal to 729, then x can be:

If the 7th term in the binomial expansion of $\displaystyle \left(\frac{3}{\sqrt[3]{84}}+\sqrt{3} \ln x\right)^9, x>0$, is equal to $\displaystyle 729$, then $\displaystyle x$ can be :
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.