Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q69
If the fourth term in the Binomial expansion of (2/x+x^log_8 x)^6(x>0) is 20 × 8^7, then a value of x is:
If the fourth term in the Binomial expansion of $\displaystyle \left(\frac{2}{x}+x^{\log _8 x}\right)^6(x>0)$ is $\displaystyle 20 \times 8^7$, then a value of $\displaystyle x$ is :
Official answer
(1)
$\displaystyle 8^2$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.