Mathematics · 2021
JEE Main · 16 March 2021, Shift 2 · Q68
If y=y(x) is the solution of the differential equation (d y)/(d x)+( tan x) y= sin x, 0 ≤ x ≤ (π)/3, with y(0)=0, then y((π)/4) equal to:
If $\displaystyle y=y(x)$ is the solution of the differential equation $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}+(\tan x) y=\sin x, 0 \leq x \leq \frac{\pi}{3}$, with $\displaystyle y(0)=0$, then $\displaystyle y\left(\frac{\pi}{4}\right)$ equal to :
Official answer
(1)
$\displaystyle \left(\frac{1}{2 \sqrt{2}}\right) \log _{\mathrm{e}} 2$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.