Mathematics · 2020
JEE Main · 6 September 2020, Shift 2 · Q63
If y=(2/(π) x-1) cosec x is the solution of the differential equation, (d y)/(d x)+ p (x) y=2/(π) cosec x, 0<x<(π)/2, then the function p (x) is…
If $\displaystyle y=\left(\frac{2}{\pi} x-1\right) \operatorname{cosec} x$ is the solution of the differential equation, $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}+\mathrm{p}(x) y=\frac{2}{\pi} \operatorname{cosec} x, 0<x<\frac{\pi}{2}$, then the function $\displaystyle \mathrm{p}(x)$ is equal to:
Official answer
(4)
$\displaystyle \cot x$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.