Mathematics · 2021
JEE Main · 16 March 2021, Shift 1 · Q77
If y=y(x) is the solution of the differential equation, (d y)/(d x)+2 y tan x= sin x, y((π)/3)=0, then the maximum value of the function y(x) over R…
If $\displaystyle y=y(x)$ is the solution of the differential equation, $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y \tan x=\sin x, y\left(\frac{\pi}{3}\right)=0$, then the maximum value of the function $\displaystyle y(x)$ over $\displaystyle \mathbf{R}$ is equal to :
Official answer
(4)
$\displaystyle \frac{1}{8}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.