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Mathematics · 2019

JEE Main · 10 April 2019, Shift 1 · Q77

If y=y(x) is the solution of the differential equation (d y)/(d x)=( tan x-y) sec^2 x, x ∈(-(π)/2, (π)/2), such that y(0)=0, then y(-(π)/4) is equal…

If $\displaystyle y=y(x)$ is the solution of the differential equation $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}=(\tan x-y) \sec ^2 x$, $\displaystyle x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, such that $\displaystyle y(0)=0$, then $\displaystyle y\left(-\frac{\pi}{4}\right)$ is equal to :
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