Mathematics · 2022
JEE Main · 25 June 2022, Shift 2 · Q13
If y=y(x) is the solution of the differential equation 2 x^2 (d y)/(d x)-2 x y+3 y^2=0 such that y(e)=e/3, then y(1) is equal to
If $\displaystyle y=y(x)$ is the solution of the differential equation $\displaystyle 2 x^2 \frac{d y}{d x}-2 x y+3 y^2=0$ such that $\displaystyle y(e)=\frac{e}{3}$, then $\displaystyle y(1)$ is equal to
Official answer
(2)
$\displaystyle \frac{2}{3}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.