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Mathematics · 2019
JEE Main · 9 January 2019, Shift 1 · Q77
If y=y(x) is the solution of the differential equation, x (d y)/(d x)+2 y=x^2 satisfying y(1)=1, then y(1/2) is equal to:
If $\displaystyle y=y(x)$ is the solution of the differential equation, $\displaystyle x \frac{\mathrm{~d} y}{\mathrm{~d} x}+2 y=x^2$ satisfying $\displaystyle y(1)=1$, then $\displaystyle y\left(\frac{1}{2}\right)$ is equal to:
Official answer
(4)
$\displaystyle \frac{49}{16}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.